Tuesday, January 5, 2010

NoRouteToHostException

java.net.NoRouteToHostException thrown when tried to access remote host and port, where firewall blocks the access. In general, -Dhttp.proxyHost and -Dhttp.proxyPort is incorrect then we do get this exception in Linux environment.


import java.io.InputStream;
import java.net.URL;
public class SocketPrg {
 public static void main(String[] args) throws Exception{
  URL url =new URL("http://schemas.xmlsoap.org/soap/envelope/");
  InputStream is=url.openStream();
 }
}

javac SocketPrg.java

java SocketPrg

In Linux, the following exception will be thrown

Exception in thread "main" java.net.NoRouteToHostException: No route to host
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:333)
at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:195)
at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:182)
at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:366)
at java.net.Socket.connect(Socket.java:519)
at java.net.Socket.connect(Socket.java:469)
at sun.net.NetworkClient.doConnect(NetworkClient.java:163)
at sun.net.www.http.HttpClient.openServer(HttpClient.java:394)
at sun.net.www.http.HttpClient.openServer(HttpClient.java:529)
at sun.net.www.http.HttpClient.<init>(HttpClient.java:233)
at sun.net.www.http.HttpClient.New(HttpClient.java:306)
at sun.net.www.http.HttpClient.New(HttpClient.java:323)
at sun.net.www.protocol.http.HttpURLConnection.getNewHttpClient(HttpURLConnection.java:852)
at sun.net.www.protocol.http.HttpURLConnection.plainConnect(HttpURLConnection.java:793)
at sun.net.www.protocol.http.HttpURLConnection.connect(HttpURLConnection.java:718)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1041)
at java.net.URL.openStream(URL.java:1009)
at SocketPrg.main(SocketPrg.java:16)

In Windows, the following exception will be thrown for the above program

Exception in thread "main" java.net.ConnectException: Connection timed out: connect
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.PlainSocketImpl.doConnect(Unknown Source)
at java.net.PlainSocketImpl.connectToAddress(Unknown Source)
at java.net.PlainSocketImpl.connect(Unknown Source)
at java.net.Socket.connect(Unknown Source)
at java.net.Socket.connect(Unknown Source)
at sun.net.NetworkClient.doConnect(Unknown Source)
at sun.net.www.http.HttpClient.openServer(Unknown Source)
at sun.net.www.http.HttpClient.openServer(Unknown Source)
at sun.net.www.http.HttpClient.<init>(Unknown Source)
at sun.net.www.http.HttpClient.New(Unknown Source)
at sun.net.www.http.HttpClient.New(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.getNewHttpClient(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.plainConnect(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.connect(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
at java.net.URL.openStream(Unknown Source)
at SocketPrg.main(SocketPrg.java:16)

Run the above, program with commandline arguments with proper proxy settings

Solution:
java -Dhttp.proxyHost=www-proxy.us.abc.com -Dhttp.proxyPort=80 SocketPrg

Reactions:

2 comments:

Post a Comment

Recent Posts

Unix Commands | List all My Posts

Texts

This blog intended to share the knowledge and contribute to JAVA Community such a way that by providing samples and pointing right documents/webpages. We try to give our knowledege level best and no guarantee can be claimed on truth. Copyright and Terms of Policy refer blogspot.com

Share

Twitter Delicious Facebook Digg Stumbleupon Favorites More